CBSE Class 11-science Answered
question
Asked by harinder | 03 Jan, 2009, 08:31: PM
Expert Answer
Say we have V P/S1 = V P/S2 + V S2/S1
Differentiating both sides we get
a P/S1 = a P/S2 + a S2/S1
4 m/s^2 = 4m/s^2 + a S2/S1
If acceleration of two frames S1 and S2 is 4m/s^2, we can only say that velocity of frame S1 relative to S2 is constant. The acceleration of the two frames with respect to each other is zero.
Answered by | 16 Jan, 2009, 11:31: AM
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