Question

Asked by anirbanbag81 | 9th Jan, 2018, 10:34: AM

Expert Answer:

Option (3) is correct.
 

space We space know comma

increment straight S space equals space straight q over straight T equals space nRTln open parentheses straight V subscript straight f over straight V subscript straight i close parentheses

increment straight S space equals space space nR space ln open parentheses straight V subscript straight f over straight V subscript straight i close parentheses

space space For space ideal space gas comma

space space straight P subscript 1 straight V subscript 1 equals space straight P subscript 2 straight V subscript 2

space space open parentheses straight V subscript straight f over straight V subscript straight i close parentheses space equals space open parentheses fraction numerator space straight P subscript straight i over denominator space straight P subscript straight f end fraction close parentheses

therefore space increment straight S space equals space space nR space ln space space open parentheses fraction numerator space straight P subscript straight i over denominator space straight P subscript straight f end fraction close parentheses

Answered by Varsha | 9th Jan, 2018, 12:05: PM