Question
Asked by pritish_kul2 | 6th Dec, 2009, 01:22: PM
tan (A+B) = (tanA + tan B)/(1 - tanA tanB)
cot(A+B) = 1/tan(A+B) = (1 - tanA tanB)/(tanA + tan B) = 0
(1 - tanA tanB)/(tanA + tan B) = 0
(1 - tanA tanB) = 0
tanA tanB = 1
tanB = 1/tanA = 4/3
cotB = 1/tanB = 3/4
Regards,
Team,
TopperLearning.
Answered by | 6th Dec, 2009, 09:07: PM
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