CBSE Class 10 Answered
QUESTION
Asked by sonaisha | 24 Nov, 2008, 08:52: PM
Expert Answer
LHS
=(1+SIN2A+COS2A+2SINA-2COSA-2SINACOSA) / (1+SIN2A+COS2A+2SINA+2COSA+2SINACOSA)
=(2+2SINA-2COSA-2SINACOSA) / (2+2SINA+2COSA+2SINACOSA)
=(1+SINA-COSA-SINACOSA) / (1+SINA+COSA+SINACOSA)
=(1-COSA)(1+SINA)/(1+COSA)(1+SINA)
=(1-COSA)/(1+COSA)
=RHS
HENCE PROVED
Answered by | 03 Dec, 2008, 02:37: AM
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