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CBSE Class 10 Answered

QUESTION
Asked by sonaisha | 24 Nov, 2008, 08:52: PM
answered-by-expert Expert Answer

LHS

=(1+SIN2A+COS2A+2SINA-2COSA-2SINACOSA) / (1+SIN2A+COS2A+2SINA+2COSA+2SINACOSA)

=(2+2SINA-2COSA-2SINACOSA) / (2+2SINA+2COSA+2SINACOSA)

=(1+SINA-COSA-SINACOSA) / (1+SINA+COSA+SINACOSA)

=(1-COSA)(1+SINA)/(1+COSA)(1+SINA)

=(1-COSA)/(1+COSA)

=RHS

HENCE PROVED

Answered by | 03 Dec, 2008, 02:37: AM
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