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CBSE Class 10 Answered

QUESTION
 
Asked by gpnkumar0 | 11 May, 2017, 07:07: AM
answered-by-expert Expert Answer
The equivalent resistance of the combination shown in the figure is explained as follows:
 
  • Resistance R1 and R2 are connected in series with each other.
           begin mathsize 12px style Equivalent space resistance space of space resistors space connected space in space series open parentheses space straight R subscript series close parentheses equals open parentheses straight R subscript 1 plus straight R subscript 2 close parentheses space straight capital omega end style
 
  • Resistance R3 and R4 are connected in parallel with each other.
          begin mathsize 12px style Equivalent space resistance space of space resistors space connected space in space parallel open parentheses space 1 over straight R subscript parallel close parentheses equals 1 over straight R subscript 3 plus 1 over straight R subscript 4 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open parentheses straight R subscript parallel close parentheses space space equals fraction numerator straight R subscript 3 straight R subscript 4 over denominator straight R subscript 3 plus straight R subscript 4 end fraction straight capital omega end style
  • Now Rs and Rp are connected in series with each other, therefore their equivalent resistance i.e the final resistance of the entire circuit is
          begin mathsize 12px style Final space resistance space of space the space circuit space open parentheses straight R close parentheses equals space straight R subscript series plus straight R subscript parallel space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals open parentheses straight R subscript 1 plus straight R subscript 2 close parentheses plus open parentheses fraction numerator straight R subscript 3 straight R subscript 4 over denominator straight R subscript 3 plus straight R subscript 4 end fraction close parentheses space straight capital omega end style
 


Answered by Abhijeet Mishra | 11 May, 2017, 09:51: AM

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