Asked by RACHIT_MAHAAN | 5th Jan, 2010, 11:22: AM
Placing a mirror as mentioned in the problem is eqivilent of two lences of same focal length sepatrated by twice the distance between mirror and convex lence.
If the distance between mirror and convex lence = d
so the distance ebtween the lences = 2d.
Say tha focal length of given lence = f
Conbined focal length =F
1/ F = 1/f1 + 1/f2 - D/f1f2 = 1/f +1/f - 2d / f2 = 2(f-d) / f2
====> F = f2 / 2(f-d)
d) The distance between the 2nd lence and focal point is called back Focal Length.(BFL)
BFL= f2(D-f1) / (D- (f1+f2) = f(2d-f)/ (2d-2f)
a) pin should be placed at a distance equivalent to BFL from the lence.
b) Image is real, size of the image same as object
Answered by | 13th Jan, 2010, 03:14: PM
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