Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

question
Asked by gpnkumar0 | 28 Jul, 2017, 09:15: PM
answered-by-expert Expert Answer
1) The two resistances are connected in series. So, the combination resistance can be found by adding the two resistances. You will get Rs = 5 Ω
 
2) The current through the circuit can be found by using the formula, I = V/Rs = 10/5 = 2 A
 
3) As the two resistors are connected in series, the current through 3 Ω resistor also remains the same, i.e. 2 A.
Answered by Romal Bhansali | 29 Jul, 2017, 01:06: PM
CBSE 10 - Physics
Asked by sakshikatewa0 | 08 Feb, 2024, 12:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by kamalaranjanmohantymohanty5 | 06 Jan, 2024, 10:05: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by nandhikasugumar | 05 Oct, 2023, 04:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by daniya062008 | 02 Oct, 2023, 08:25: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 28 Aug, 2023, 09:49: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by praveenkumae975 | 06 Feb, 2023, 07:19: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
active attachment
Asked by ruparus | 04 Nov, 2022, 09:52: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×