CBSE Class 10 Answered
QUESTION
Asked by sonaisha | 24 Nov, 2008, 08:48: PM
Expert Answer
put secA= 1/cosA and cosecA = 1/sinA
LHS
=( cos2A/ 1-cos4A + sin2A /1-sin4A) sin2A cos2A
=( cos2A (1-sin4A) + sin2A (1-cos4A) ) sin2A cos2A / (1-sin4A)(1-cos4A)
=(cos2A -cos2Asin4A+ sin2A -sin2Acos4A)sin2A cos2A / (1-sin2A)(1-cos2A)(1+sin2A)(1+cos2A)
=(1-cos2Asin2A) / (1+sin2A)(1+cos2A)
=(1-cos2Asin2A) / (1+sin2A+cos2A+sin2Acos2A)
=1-sin 2 A cos 2 A / 2 + sin2 A cos 2A
Answered by | 03 Dec, 2008, 01:59: AM
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