QUESTION

Asked by sonaisha | 24th Nov, 2008, 08:48: PM

Expert Answer:

put secA= 1/cosA   and cosecA = 1/sinA

LHS

=( cos2A/ 1-cos4A  + sin2A /1-sin4A) sin2A cos2A

=( cos2A (1-sin4A) + sin2A (1-cos4A) ) sin2A cos2A / (1-sin4A)(1-cos4A)

=(cos2A -cos2Asin4A+ sin2A -sin2Acos4A)sin2A cos2A / (1-sin2A)(1-cos2A)(1+sin2A)(1+cos2A)

=(1-cos2Asin2A) / (1+sin2A)(1+cos2A)

=(1-cos2Asin2A) / (1+sin2A+cos2A+sin2Acos2A)

=1-sin 2 A  cos 2 A /  2 +  sin2 A  cos 2A

Answered by  | 3rd Dec, 2008, 01:59: AM

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