question

Asked by poojathally | 19th Feb, 2010, 10:22: PM

Expert Answer:

"Two water taps together can fill a tank in hours."

So we assume you meant it takes an hour for two taps together to fill the tank.

V - volume of tank, v1 - flow rate from tap 1, v2 - flow rate from tap 2

Time = Volume/Flow rate.

For tap 1,

T1 = V/v1

Similarly for tap 2,

T2 = V/v2

Two taps together,

1 hr = V/(v1+v2) = 1/(v1/V + v2/V) = 1/(1/T1 + 1/T2)

T2 = T1 + 10   ........

1 hr = 1/(1/T1 + 1/(T1+10))

1 = T1(T1+10)/(T1 + T1+10)

T12 + 8T1 - 10 = 0.

T1 = [-8±(64+40)]/2

= 1.099 hr .......and we reject other root since time can't be negative.

T2 = 11.099 hr.

The time required by large diameter tap is 1.099 hr or 1 hr 6 min and required by small diameter tap is,

11 hrs 6 min.

Regards,

Team,

TopperLearning.

Answered by  | 20th Feb, 2010, 06:04: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.