Asked by poojathally | 19th Feb, 2010, 10:22: PM
"Two water taps together can fill a tank in hours."
So we assume you meant it takes an hour for two taps together to fill the tank.
V - volume of tank, v1 - flow rate from tap 1, v2 - flow rate from tap 2
Time = Volume/Flow rate.
For tap 1,
T1 = V/v1
Similarly for tap 2,
T2 = V/v2
Two taps together,
1 hr = V/(v1+v2) = 1/(v1/V + v2/V) = 1/(1/T1 + 1/T2)
T2 = T1 + 10 ........
1 hr = 1/(1/T1 + 1/(T1+10))
1 = T1(T1+10)/(T1 + T1+10)
T12 + 8T1 - 10 = 0.
T1 = [-8±(64+40)]/2
= 1.099 hr .......and we reject other root since time can't be negative.
T2 = 11.099 hr.
The time required by large diameter tap is 1.099 hr or 1 hr 6 min and required by small diameter tap is,
11 hrs 6 min.
Answered by | 20th Feb, 2010, 06:04: AM
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