Question related to geometry

In triangle ABC,

AP/PB=AQ/QC..... (i)   since PQ II BC so by BPT  we get the result.

simly,

in triangle AQC

AQ/QC=AR/RD...(ii)

 so by (i) and (ii)

 we get,

AP/PB=AR/RD

So in trianglr ABD, by converse of BPT, we get the result.