Question related to geometry
Asked by | 18th Oct, 2009, 07:52: AM
Expert Answer:
In triangle ABC,
AP/PB=AQ/QC..... (i) since PQ II BC so by BPT we get the result.
simly,
in triangle AQC
AQ/QC=AR/RD...(ii)
so by (i) and (ii)
we get,
AP/PB=AR/RD
So in trianglr ABD, by converse of BPT, we get the result.
Answered by | 19th Oct, 2009, 03:17: PM
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