Question related to geometry

Asked by  | 18th Oct, 2009, 07:52: AM

Expert Answer:

In triangle ABC,

AP/PB=AQ/QC..... (i)   since PQ II BC so by BPT  we get the result.

simly,

in triangle AQC

AQ/QC=AR/RD...(ii)

 so by (i) and (ii)

 we get,

AP/PB=AR/RD

So in trianglr ABD, by converse of BPT, we get the result.

 

Answered by  | 19th Oct, 2009, 03:17: PM

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