Question related to geometry
Asked by | 18th Oct, 2009, 07:52: AM
In triangle ABC,
AP/PB=AQ/QC..... (i) since PQ II BC so by BPT we get the result.
in triangle AQC
so by (i) and (ii)
So in trianglr ABD, by converse of BPT, we get the result.
Answered by | 19th Oct, 2009, 03:17: PM
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