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CBSE Class 11-science Answered

question of chemistry in image attached below.
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Asked by sumitshekhar891 | 09 Nov, 2019, 04:01: PM
answered-by-expert Expert Answer
Number of moles of TiCl3 = 38.6/(48+35.5*3)
                                    =38.6/(106.5+48)
                                    =38.6/154.5
                                    =0.2498
 
Number of molecules of TiCl3 = 0.2498 NA
1 molecule of TiCl3 has 3 Cl atoms
0.2498 NA molecules will have = 0.2498*3*NA =4.512*1023  Cl atoms
Answered by Ravi | 11 Nov, 2019, 06:59: PM
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