question of chemistry in image attached below.

Asked by sumitshekhar891 | 9th Nov, 2019, 04:01: PM

Expert Answer:

Number of moles of TiCl3 = 38.6/(48+35.5*3)
                                    =38.6/(106.5+48)
                                    =38.6/154.5
                                    =0.2498
 
Number of molecules of TiCl3 = 0.2498 NA
1 molecule of TiCl3 has 3 Cl atoms
0.2498 NA molecules will have = 0.2498*3*NA =4.512*1023  Cl atoms

Answered by Ravi | 11th Nov, 2019, 06:59: PM