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CBSE Class 9 Answered

Question number 35 in given file
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Asked by pranavhoge1205n3004 | 20 Feb, 2020, 10:45: PM
answered-by-expert Expert Answer
To solve the given expression: -3/(root3+root2) - 3root2/(root6+root3) +4root3/(root6+root2)
fraction numerator negative 3 over denominator square root of 3 plus square root of 2 end fraction minus fraction numerator 3 square root of 2 over denominator square root of 6 plus square root of 3 end fraction plus fraction numerator 4 square root of 3 over denominator square root of 6 plus square root of 2 end fraction equals fraction numerator negative 3 over denominator square root of 3 plus square root of 2 end fraction cross times fraction numerator square root of 3 minus square root of 2 over denominator square root of 3 minus square root of 2 end fraction minus fraction numerator 3 square root of 2 over denominator square root of 6 plus square root of 3 end fraction cross times fraction numerator square root of 6 minus square root of 3 over denominator square root of 6 minus square root of 3 end fraction plus fraction numerator 4 square root of 3 over denominator square root of 6 plus square root of 2 end fraction cross times fraction numerator square root of 6 minus square root of 2 over denominator square root of 6 minus square root of 2 end fraction equals negative 3 square root of 3 plus 3 square root of 2 minus fraction numerator 3 square root of 2 open parentheses square root of 6 minus square root of 3 close parentheses over denominator 3 end fraction plus fraction numerator 4 square root of 3 open parentheses square root of 6 minus square root of 2 close parentheses over denominator 4 end fraction equals negative 3 square root of 3 plus 3 square root of 2 minus 2 square root of 3 plus square root of 2 cross times square root of 3 plus 3 square root of 2 minus square root of 3 cross times square root of 2 equals negative 5 square root of 3 plus 6 square root of 2
Answered by Renu Varma | 24 Feb, 2020, 10:21: AM

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