Question is :

Asked by spuneet23 | 27th Sep, 2010, 11:17: PM

Expert Answer:

logx2xx-x0Note x0, as the base is x2Case (1) x>0so x=x and xx=1logx21-x0, hence 1-x1 as log1=0-x0, x0but x>0 and x0So no solution for this case(1)Case (2) x<0so x=-x, and xx=-1logx2-1-x0so -1-x1-x2,x-2Conclusion: the solution set is x-2">

Answered by  | 28th Sep, 2010, 10:15: AM

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