QUESTION: Compare the relative stability of the following species and indicate 
their magnetic properties;
  1. o2
  2. o2+
  3. o2-(superoxide)

Asked by SIDDHESH | 18th Sep, 2014, 08:51: PM

Expert Answer:

O2 = (σ1s)2(σ*1s)2 (σ2s)2(σ*2s)2(σ2z)2(π2px2= π2py2) (π*2px1= π*2py1)

Bond order = (Nb-Na) /2 = (10-6)/2= 2

It is paramagnetic as it contains two unpaired electrons.

O2+ = = (σ1s)2(σ*1s)2 (σ2s)2(σ*2s)2(σ2z)2(π2px2= π2py2) (π*2px1)

Bond order = 2.5

It is paramagnetic as it contains one unpaired electron.

O2+ = = (σ1s)2(σ*1s)2 (σ2s)2(σ*2s)2(σ2z)2(π2px2= π2py2) (π*2px2= π*2py1)

Bond order = 1.5

It is paramagnetic as it contains one unpaired electron.

Answered by Prachi Sawant | 19th Sep, 2014, 12:49: PM