QUESTION 1 : 
 
                    

Asked by gpnkumar0 | 15th Sep, 2016, 07:45: AM

Expert Answer:

begin mathsize 16px style open parentheses square root of straight x close parentheses to the power of fraction numerator negative 2 over denominator 3 end fraction end exponent square root of straight y to the power of 4 end root plus square root of xy to the power of fraction numerator negative 1 over denominator 2 end fraction end exponent end root square root of straight x to the power of negative 2 end exponent straight y cubed end root
equals straight x to the power of 1 half cross times fraction numerator negative 2 over denominator 3 end fraction end exponent straight y to the power of 4 cross times 1 half end exponent plus straight x to the power of 1 half end exponent straight y to the power of fraction numerator negative 1 over denominator 4 end fraction end exponent straight x to the power of negative 2 cross times 1 half end exponent straight y to the power of 3 cross times 1 half end exponent
equals straight x to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent straight y squared plus straight x to the power of 1 half minus 1 end exponent straight y to the power of fraction numerator negative 1 over denominator 4 end fraction plus 3 over 2 end exponent
equals straight x to the power of fraction numerator negative 1 over denominator 3 end fraction end exponent straight y squared plus straight x to the power of fraction numerator negative 1 over denominator 2 end fraction end exponent straight y to the power of 5 over 4 end exponent end style

Answered by Rebecca Fernandes | 15th Sep, 2016, 11:28: AM