Ques on Triangles.......
Asked by sanskritforall | 6th Mar, 2010, 07:35: PM
Coordinates of B(0,0).
Coordinats of C, (x,0), since C lies on the x-axis, as the side BC lies on the positive side of x axis,
Coordinates of A(X,Y).
Using distance formula,
BC = ((x-0)2 + (0-0)2) = a
BC = x = a
AB2 = x2 + y2 = a2 ............distance formula
and AC2 = (x-a)2 + y2 = a2 .............distance formula
But AB = AC ... equilateral triangle,
AB2 = AC2
x2 + y2 = (x-a)2 + y2
x2 + y2 = x2 - 2xa + a2 + y2
- 2xa + a2= 0
x = a/2
x2 + y2 = a2
y = 3a/2
Hence, the coordiantes are A(a/2, 3a/2), B(0,0), C(a,0).
Answered by | 7th Mar, 2010, 05:45: AM
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