Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

ques is as follows
Asked by | 22 Jan, 2010, 07:22: PM
answered-by-expert Expert Answer

Dear Student

He Paid  60,000 Rs

Balance amount is 60000

At the end of the first month He ahs to pay 

5000+ 12% interest on (12X 5000)

At the end if secind month  5000+ 12% interest on (11X 5000)

Similarly at the end of n the month

=5000+ 12% interest on (nX 5000)=5000(1+     12n/100 ) =50(100+12n)=5000+600n

Aum over all n values from n=1 to 12

Total paid install met amount=  Aigma ( 5000+600n)=  (12X5000)  + 600(1+2+...12) =60,000+600X78=1,06,800

Total ost of shop= 60000+1,06,800 =1,66,800.Rs

Regards

Team

Topperlearning

Answered by | 22 Jan, 2010, 08:36: PM
CBSE 10 - Maths
Asked by ramagiriamulya2477 | 27 Jan, 2023, 07:58: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shashwatpns | 22 Apr, 2010, 04:58: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by RACHIT_MAHAAN | 15 Mar, 2010, 02:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by kirtichawla94 | 12 Mar, 2010, 03:50: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by akhileshnarayanan | 12 Mar, 2010, 02:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ashwinivg | 10 Mar, 2010, 08:46: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by poojathally | 10 Mar, 2010, 11:42: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by y.revanth | 08 Mar, 2010, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×