CBSE Class 10 Answered
quadrilateral
Asked by | 13 Feb, 2009, 10:28: PM
Expert Answer
The sum of the zeroes of a polynomial in x =-b/a
and
the product of the zeroes=c/a
where
a is coefficient of x squared and b is coefficient of the term in x and c is the term free of x.
So, here,
a=1, b=-8 and c=k
So sum of the zeroes = -b/a= -(-8)/1=8
product of the zeroes=c/a=k
We need to find the sum of squares of the zeroes.
.gif)
Answered by | 14 Feb, 2009, 08:46: AM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT