CBSE Class 10 Answered
quadratic
Asked by duttaneelanjana | 11 Jul, 2009, 01:58: AM
Expert Answer
For the QE to have equal roots D =0.i.e b2 -4ac = 0
here a = 1 , b = 2(1+3k) , c = 7(3 +2k)
If b2 -4ac = 0
[2(1 +3k)]2 -4 x 1 x 7(3 +2k) = 0
4 (1+ 6k +9k2) - 4 x 1 x (21 +14k) = 0...........divide through out by 4
1+ 6k +9k2 -21 -14k = 0
9k2 - 8k - 20 = 0
9k2 -18k +10k -20 =0
9k (k -2) -10 (k -2) =0
(9k-10)(k -2) = 0
k = -10/9 or k = 2.
Answered by | 11 Jul, 2009, 10:52: AM
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