quadratic equations...

Asked by deepitapai | 9th Mar, 2009, 12:21: PM

Expert Answer:

Let base = x, altitude = y Hypotenuse = (x2+y2) Now hypotenuse = x+2=y+4 ⇒ x = y+2 x2+y2= (x+2)2 and x2+y2= (y+4)2 We get  x2= 16+8y  and y2= 4x+y Substituting x = y+2 in first eqyation and solving, we get x=8 and y = 6 Hence, the lengths of the rods are 6 cm, 8 cm and 10 cm

Aswered by  | 9th Mar, 2009, 02:22: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.