quadratic equations

Asked by  | 4th Jul, 2008, 04:59: PM

Expert Answer:

Let the side of first square is x and the side of second square is y

so 4x - 4y = 64

or x - y = 16

x = 16+ y

and as we know that the sum of the areas of both the triangles = 640

x2 + y2 = 640

Put x = 16+y

(16+y)2 + y2 = 640

2y2+32y - 384 = 0

y2 + 16y -192 = 0

(y+24)(y-8) = 0

y = -24 or 8 (rejecting negative value)

y = 8m

so x = 16+y

= 16+8

=24m

 

 

Answered by  | 4th Jul, 2008, 05:43: PM

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