CBSE Class 10 Answered
quadratic equations
Asked by | 12 Mar, 2009, 10:09: PM
Expert Answer
Second equation must be x2+px+k=0 instead of x2+pk+k=0
If -4 is a root of the quadratic equation x2+px-4=0 then
-4 must satify it i.e 16-4p-4=0 which gives p = 3
Using the value of p in quadratic equation x2+px +k=0 we have x2+3x+k=0
For equal roots Discrimiminant =0
i.e 9-4k =0 So k = 9/4
Answered by | 12 Mar, 2009, 10:17: PM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT