quadratic equations

Asked by  | 12th Mar, 2009, 10:09: PM

Expert Answer:

Second equation must be x2+px+k=0 instead of x2+pk+k=0

If -4 is a root  of the  quadratic equation x2+px-4=0 then

-4  must satify it i.e 16-4p-4=0 which gives p = 3

Using the value of p in quadratic equation x2+px +k=0 we have x2+3x+k=0

For equal roots Discrimiminant =0

i.e 9-4k =0 So k = 9/4

Answered by  | 12th Mar, 2009, 10:17: PM

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