CBSE Class 10 Answered
quadratic equation.
Asked by khushal305 | 09 Sep, 2009, 08:41: PM
Expert Answer
abx2 = (a+b)2(x-1)
A = (a+b)2
abx2 = A(x-1)
abx2 - Ax + A = 0
x = [A ± 
(A2 - 4abA)]/2ab
{ A2 - 4abA = A(A - 4ab) = (a+b)2((a+b)2 - 4ab) = (a+b)2(a2 + 2ab + b2 - 4ab) = (a+b)2(a-b)2 }
x = [A ± (A2 - 4abA)]/2ab
x = [(a+b)2 ± (a+b)(a-b)]/2ab
x = (a+b) [a+b ± (a-b)]/2ab
x = {(a+b)/b, (a+b)/a}
Regards,
Team,
TopperLearning.
Answered by | 09 Sep, 2009, 10:31: PM
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