CBSE Class 8 Answered
Qns. 1
Asked by krishna015071989 | 11 Jan, 2020, 10:25: PM
Expert Answer
Area of a ΔABC = 1/2 × base × height = 1/2 × AC × BM = 1/2 × 8 × 3 = 12 cm2 ... (i)
Area of a rectangle CDON = length × breadth = 5 × 4 = 20 cm2 ... (ii)
AF = NP ... Opposite sides of a rectangle
NP = 8.4
PE = 1.8 ... PE = NE - NP
AN = AC - NC = 8 - 5 = 3cm .... OD = NC ... Opposite sides of a rectangle
AN = PF = 3cm ... Opposite sides of a rectangle
Area of a rectangle ANPF = length × breadth = 8.4 × 3 = 25. 2 cm2 ... (iii)
Area of a ΔEPF = 1/2 × base × height = 1/2 × PE × PF = 1/2 × 1.8 × 3 = 2.7 cm2 ... (iv)
Area of a ΔDOE = 1/2 × OE × OD = 1/2 × 5 × 5 = 12.5 cm2 ... (v)
Area of a hexagon ABCDEF = 12 cm2 + 20 cm2 + 25. 2 cm2 + 2.7 cm2 + 12.5 cm2 = 72.4 cm2
Answered by Yasmeen Khan | 14 Jan, 2020, 11:17: AM
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