CBSE Class 9 Answered
q34
Asked by | 01 Sep, 2009, 07:16: PM
Expert Answer
log (4y-3)=log(2y+1) - log3
log(4y-3)=log(2y+1)/3 taking antilogs, 4y-3=(2y+1)/3 12y - 9 = 2y + 1 10y = 10 y = 1 Regards, Team, TopperLearning.
Answered by | 02 Sep, 2009, 12:09: AM
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