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CBSE Class 9 Answered

q34
Asked by | 01 Sep, 2009, 07:16: PM
Expert Answer

log (4y-3)=log(2y+1) - log3

log(4y-3)=log(2y+1)/3

taking antilogs,

4y-3=(2y+1)/3

12y - 9 = 2y + 1

10y = 10

y = 1

Regards,

Team,

TopperLearning.

 

Answered by | 02 Sep, 2009, 12:09: AM
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