ICSE Class 9 Answered
Q16. 4a² - 12a + 9 - 49b²
Asked by Swatisasturkar | 04 Feb, 2023, 01:38: PM
4a² - 12a + 9 - 49b²
This can be re-written as
(2a)2 + (3)2 -2(2a)(3) - (7b)2
(2a - 3)2 - (7b)2
(2a - 3 + 7b)(2a - 3 - 7b)
We used the identites (a - b)2 = a2 - 2ab + b2 and a2 - b2 = (a + b)(a - b)
Answered by | 05 Feb, 2023, 12:03: AM
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