Q1. find the vertex and directix of the parabola Y²=8(x+1).

We know that,

the general equation of a parabola is (y - k)² = 4p(x- h) where (h, k ) is the vertex and x = h - p is the directrix.

Given equation is y² = 8(x+1).

That is, (y - 0)² = 4(2)(x- (-1))

So, h = 0, k = -1, p = 2

vertex = (0, -1)

directrix is x = 0 - 2, that is x= -2