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CBSE Class 11-science Answered

Q
Asked by araima2001 | 09 Sep, 2016, 11:11: AM
answered-by-expert Expert Answer
 
tan straight theta over 2 space equals space cosecθ minus sinθ rightwards double arrow tan straight theta over 2 equals fraction numerator 1 plus tan squared straight theta over 2 over denominator 2 tan straight theta over 2 end fraction minus fraction numerator 2 tan straight theta over 2 over denominator 1 plus tan squared straight theta over 2 end fraction rightwards double arrow open parentheses 2 tan squared straight theta over 2 close parentheses open parentheses 1 plus tan squared straight theta over 2 close parentheses equals open parentheses 1 minus tan squared straight theta over 2 close parentheses squared Let space tan squared straight theta over 2 space equals space straight x rightwards double arrow 2 straight x open parentheses 1 plus straight x close parentheses equals open parentheses 1 minus straight x close parentheses squared rightwards double arrow straight x squared plus 4 straight x minus 1 equals 0 rightwards double arrow straight x equals negative 2 plus-or-minus square root of 5 rightwards double arrow straight x equals negative 2 plus square root of 5 space space space............ open parentheses as space straight x space greater or equal than space 0 close parentheses rightwards double arrow space tan squared straight theta over 2 equals negative 2 plus square root of 5 sec squared straight theta over 2 equals 1 plus tan squared straight theta over 2 equals 1 plus negative 2 plus square root of 5 equals square root of 5 minus 1 Option space straight B space is space correct.
Answered by Vijaykumar Wani | 14 Sep, 2016, 12:19: PM

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CBSE 11-science - Maths
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