Q. What will be the duration of the day, if the earth suddenly shrinks to 1/64th of its original volume and mass remaining unchanged ?

Asked by Vipul Kaushik | 19th Oct, 2010, 12:52: PM

Expert Answer:

Dear Student
 
Since there is no external torque, angular momentum will remain unchanged.
r = R/4  (v = V/64)
D, d => duration of the day.
Initial angular momentum = (2/5 MR2) x (2π / D)
Hence
(4/5) x πMR2 / D = (4/5) x π M (R2/16)/d
1/D = 1/16d
d = D/16=24/16=1.5 hours.
 
We hope that satisfies your query.
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Team
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Answered by  | 20th Oct, 2010, 04:40: PM

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