Q- Two charges +3Q and -2Q placed at (a,0) and (4a,0) respectively. What is the flux emanating out of the sphere of radius 3a taking 0 as the origin?

Asked by Subhashree Lenka | 23rd May, 2015, 11:34: PM

Expert Answer:

According to gauss theorem we know that the electric flux through a closed surface enclosing a charge is equal to 1/ε0 times the magnitude of the charge enclosed.
The charge enclosed by the sphere = +3Q
Therefore in this case the electric flux emanating out of the sphere of radius 3a with its centre at the origin,

begin mathsize 14px style straight ϕ equals fraction numerator plus 3 straight Q over denominator straight epsilon subscript 0 end fraction end style

Answered by Jyothi Nair | 24th May, 2015, 03:55: PM