Q) the solubility product constants of A g subscript 2 C r O subscript 4 space & space A g B r space a r e space 1.1 space cross times space 10 to the power of negative 12 end exponent space & space 5 space cross times space 10 to the power of negative 13 end exponent space r e s p e c t i v e l y. space C a l c u l a t e space t h e space r a t i o space o f space m o l a r i t i e s space o f space t h e i r space s a t u r a t e d space s o l u t i o n s.

Asked by araima2001 | 28th Oct, 2016, 10:58: PM

Expert Answer:

L e t space s space b e space t h e space s o l u b i l i t y space o f space A g subscript 2 C r O subscript 4.
A g subscript 2 C r O subscript 4 space left right arrow space A g to the power of 2 plus end exponent space plus space 2 C r O subscript 4 to the power of minus
K s p space equals space left parenthesis 2 s right parenthesis squared space. s space equals space 4 s cubed
1.1 space cross times 10 to the power of negative 12 end exponent space equals space 4 s cubed
s space equals 6.5 space cross times 10 to the power of negative 5 end exponent space M
L e t space s apostrophe space b e space t h e space s o l u b i l i t y space o g space A g B r
A g B r space left right arrow space A g to the power of plus space plus space B r to the power of minus
K s p space equals space s apostrophe squared space equals space 5.0 cross times 10 to the power of negative 13 end exponent
H e n c e comma space t h e space r a t i o space o f space t h e space m o l a r i t i e s space o f space t h e i r space s a t u r a t e d space s o l u t i o n space i s
fraction numerator s over denominator s apostrophe end fraction equals space fraction numerator 6.5 cross times 10 to the power of negative 5 end exponent over denominator 7.07 cross times 10 to the power of negative 7 end exponent end fraction space equals space 91.9

Answered by Prachi Sawant | 31st Oct, 2016, 07:03: PM

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