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CBSE Class 12-science Answered

Q)Show that the function f colon R rightwards arrow left curly bracket x element of space R space colon space minus 1 less than x less than 1 right curly bracket space space d e f i n e d space b y space f left parenthesis x right parenthesis equals fraction numerator x over denominator 1 plus open vertical bar x close vertical bar end fraction comma space x element of R space i s space o n t o.
Asked by araima2001 | 04 Jun, 2017, 07:49: PM
answered-by-expert Expert Answer
begin mathsize 16px style straight f left parenthesis straight x right parenthesis equals fraction numerator straight x over denominator 1 plus open vertical bar straight x close vertical bar end fraction Case space 1 colon minus 1 less than straight x less than 0 rightwards double arrow straight f left parenthesis straight x right parenthesis equals straight y equals fraction numerator straight x over denominator 1 minus straight x end fraction rightwards double arrow straight y minus yx equals straight x rightwards double arrow straight y equals xy plus straight x rightwards double arrow straight y equals straight x open parentheses 1 plus straight y close parentheses rightwards double arrow straight x equals fraction numerator straight y over denominator 1 plus straight y end fraction Similarly comma space for space 0 less than straight x less than 1 straight x equals fraction numerator straight y over denominator 1 minus straight y end fraction rightwards double arrow straight x equals fraction numerator straight y over denominator 1 plus open vertical bar straight y close vertical bar end fraction HEnce comma space function space is space onto. end style
Answered by Sneha shidid | 05 Jun, 2017, 12:38: PM

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