Q:Find the point on the curve =4x which is nearest to (2,-8).
Asked by Ravi consul | 15th Mar, 2015, 08:02: PM
Answered by Vimala Ramamurthy | 16th Mar, 2015, 11:37: AM
- find the eqation of tangent to curve 3x2-y2=8 which passthrough point 4/3,0
- Show that the tangents to the curve y = 2x3 – 3 at the points where x = 2 and x = – 2 are parallel.
- The slope of the curve 2y2 = ax2 + b at (1, – 1) is – 1. Find a, b
- The slope of the normal to the curve x = 1 - a sin , y = b cos2 θ ï»¿ï»¿ï»¿ï»¿ï»¿ at q = is
- Find the points on the curve y = x3 – 2x2 – x at which the tangent lines are parallel to the line y = 3x – 2.
- Find the points on the curve y = x3 at which the slope of the tangent is equal to the y-coordinate of the point.
- Find the point on the curve y = x3 – 11x + 5 at which the tangent has the equation y = x – 11.
- Find the points on the curve 9y2 = x3 where normal to the curve makes equal intercepts with the axes.
- Find the equation of the normal to the curve y = 2x2 + 3 sin x at x = 0.
- Find the equations of the tangent and the normal to 16x2 + 9y2 = 144 at (x1, y1) where x1 = 2 and y1 > 0.
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