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CBSE Class 12-science Answered

Q 48
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Asked by lekhakarthikeyan | 16 Jul, 2018, 03:58: PM
answered-by-expert Expert Answer
begin mathsize 16px style According space to space the space question comma Vector space passing space through space top enclose straight r subscript 1 equals top enclose straight a subscript 1 plus straight lambda top enclose straight b subscript 1 space and space top enclose straight r subscript 2 equals top enclose straight a subscript 2 plus straight mu top enclose straight b subscript 2 open parentheses top enclose straight r minus top enclose straight a close parentheses times open parentheses top enclose straight b subscript 1 cross times top enclose straight b subscript 2 close parentheses equals 0 top enclose straight a equals straight i with hat on top plus 2 straight j with hat on top minus 4 straight k with hat on top top enclose straight b subscript 1 equals 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top top enclose top enclose straight b end enclose subscript 2 equals straight i with hat on top plus straight j with hat on top plus straight k with hat on top Find space top enclose straight b subscript 1 cross times top enclose top enclose straight b end enclose subscript 2 space we space get space minus 3 straight i with hat on top minus 4 straight j with hat on top minus straight k with hat on top Find space vector space equation space of space straight a space plane open square brackets top enclose straight r minus open parentheses straight i with hat on top plus 2 straight j with hat on top minus 4 straight k with hat on top close parentheses close square brackets times open parentheses negative 3 straight i with hat on top minus 4 straight j with hat on top minus straight k with hat on top close parentheses equals 0 rightwards double arrow top enclose straight r times open parentheses 3 straight i with hat on top plus 4 straight j with hat on top plus straight k with hat on top close parentheses equals 7 Cartesian space form open parentheses straight x straight i with hat on top plus straight y straight j with hat on top plus zk with hat on top close parentheses times open parentheses 3 straight i with hat on top plus 4 straight j with hat on top plus straight k with hat on top close parentheses equals 7 3 straight x plus 4 straight y plus straight z minus 7 equals 0 Find space distance space of space the space point space left parenthesis 9 comma negative 8 comma negative 10 right parenthesis space from space the space plane space we space get space straight p space equals space fraction numerator 22 over denominator square root of 26 end fraction units end style
Answered by Sneha shidid | 17 Jul, 2018, 09:51: AM

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CBSE 12-science - Maths
Q 48
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Asked by lekhakarthikeyan | 16 Jul, 2018, 03:58: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
If  is the normal from the origin to the plane, and  is the unit vector along . P(x, y, z) be any point on the plane and  is perpendicular to . Find the equation of plane in the normal form.
Asked by Topperlearning User | 26 Feb, 2015, 10:10: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Let  be the vector normal to the plane and  be the position vector of the point through which the plane passes. Then find the equation of plane.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Find the equation of the plane, which is at a distance of 5 unit from the origin and has as a normal vector.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Find the equation of the plane whose distance from the origin is 8 units and the direction ratios of the normal are 6, – 3, – 2.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Find the equation of the plane is . Find the perpendicular distance of the plane from the origin.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Write the normal and Cartesian form of the plane .
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Find the equation of the plane passing through the points (–1, 4, – 3), (3, 2, – 5) and (– 3, 8, – 5).
Asked by Topperlearning User | 26 Feb, 2015, 10:50: AM
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CBSE 12-science - Maths
Find the equation of the plane passing through the point (3, – 3, 1) and perpendicular to the line joining the points (3, 4, – 1) and (2, – 1, 5).
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
Find the co-ordinates of the foot of the perpendicular drawn from the origin to the plane 2x – 3y + 6z + 7 = 0.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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