Q-1 A motorcyclist drives from A-B with uniform speed of 30km/ hour and returns at 20km/ hour. Find its average speed

Asked by Satakshi Srivastava | 12th May, 2013, 08:42: PM

Expert Answer:

Lets suppose the time taken in moving from A to B is T1.
Speed = 30km/hr
So T1= AB/30
 
Lets suppose the time taken in moving from B to A is T2
Speed = 20 km/hr
T2 = AB/20
 
Total distance = 2AB
Total Time = AB/20 + AB/30
= AB [1/20 +1/30]
= AB [50/600]
=ABx 5/60
 
Average Speed = Total Distance / Total Time
= 2ABx60/ABx5 = 120/5 = 24 km/hr

Answered by  | 12th May, 2013, 08:50: PM

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