Q)

0.1 M acetic acid solution is titrated against 0.1 M NaOH solution. What would be the difference in pH between 1/4 and 3/4 stages of neutralization of acid?

Asked by Anish | 24th Aug, 2019, 10:21: PM

Expert Answer:

When acetic acid is titrated with NaOH it will behaave as Buffer solution. 
 
We space know space in space case space of space acidic space buffer minus
pH equals pK subscript straight a space plus log fraction numerator left square bracket Salt right square bracket over denominator left square bracket Acid right curly bracket end fraction
pK subscript straight a space of space acetic space acid equals 4.77

In space case space of space 1 fourth th space Titration space minus
left square bracket Salt right square bracket equals straight x over 4
left square bracket Acid right square bracket equals fraction numerator 3 straight x over denominator 4 end fraction

pH subscript 1 space equals 4.77 plus space log 1 third

In space case space of space space 3 over 4 th space Titration minus
pH subscript 2 space equals 4.77 plus log 3 over 1

Difference space in space pH equals space 2 log 3 equals 0.95

Answered by Ravi | 26th Aug, 2019, 11:38: AM