Provement
Asked by Shivam Mishra
| 14th Nov, 2013,
08:21: PM
Expert Answer:

Join AQ and CP.
A(APC)= A(ABC)/2 …… (Since CP is a median)
In triangle APC,
Since CR is a median,
A(ARC)= 1/4 A(ABC)-------(1)
A(PRQ)= 1/2 A(APQ)= 1/2 A(BPQ)
A(BPQ)= 1/4 A(ABC)
or A(PRQ)= 1/8 A(ABC)
So. A(PRQ)= 1/2 A(ARC) [Since A(ARC)= 1/4 A(ABC)]
2). A(RQC)=A(RQB)
A(ABC)= A(RQB)+ A(RQC)+ A(ARC)
or A(ABC)= 2 A(RQC) + 1/4 A(ABC) [Using (1)]
or 2 A(RQC)= 3/4 A(ABC)
or A (RQC) = 3/8 A(ABC)
Join AQ and CP.
A(APC)= A(ABC)/2 …… (Since CP is a median)
In triangle APC,
Since CR is a median,
A(ARC)= 1/4 A(ABC)-------(1)
A(PRQ)= 1/2 A(APQ)= 1/2 A(BPQ)
A(BPQ)= 1/4 A(ABC)
or A(PRQ)= 1/8 A(ABC)
So. A(PRQ)= 1/2 A(ARC) [Since A(ARC)= 1/4 A(ABC)]
2). A(RQC)=A(RQB)
A(ABC)= A(RQB)+ A(RQC)+ A(ARC)
or A(ABC)= 2 A(RQC) + 1/4 A(ABC) [Using (1)]
or 2 A(RQC)= 3/4 A(ABC)
or A (RQC) = 3/8 A(ABC)
Answered by Rashmi Khot
| 15th Nov, 2013,
06:48: PM
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