CBSE Class 11-science Answered
prove
Asked by | 30 Jul, 2012, 03:41: PM
Expert Answer
(1/sin10) - (sq.root3/cos10)= {cos10 - ? 3 sin10}/sin10 cos10
= 2 {½ cos10 - ? 3/2 sin10}/sin10 cos10
=2(cos60cos 10- sin60sin10)/{½×2sin10 cos10}
Since ½=cos60 and ? 3/2=sin60
2cos(60+10)/{½×sin20}=4cos70/sin20
= 4cos70/sin(90-70) since sin20=sin(90-70)= cos70
=4cos70/cos70= 4
= 2 {½ cos10 - ? 3/2 sin10}/sin10 cos10
=2(cos60cos 10- sin60sin10)/{½×2sin10 cos10}
Since ½=cos60 and ? 3/2=sin60
2cos(60+10)/{½×sin20}=4cos70/sin20
= 4cos70/sin(90-70) since sin20=sin(90-70)= cos70
=4cos70/cos70= 4
Answered by | 30 Jul, 2012, 04:20: PM
Concept Videos
CBSE 11-science - Maths
Asked by rajyothi64 | 05 Mar, 2024, 09:49: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by ghoshshawata62 | 04 Mar, 2024, 08:16: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by nayaktapaswini2007 | 29 Feb, 2024, 09:10: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by bimanmandal53361 | 15 Jan, 2024, 12:32: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by sreyas.katuri | 23 Sep, 2023, 07:12: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by 069.pks | 16 Sep, 2023, 10:06: AM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by surekhashriwas01 | 12 Sep, 2023, 08:39: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by mvr23467 | 12 Sep, 2023, 07:52: PM
ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by SasipriyaNagappan | 27 Jul, 2023, 07:22: PM
ANSWERED BY EXPERT