prove
Asked by | 24th Apr, 2008, 06:58: PM
Expert Answer:
sec A ( 1 - sinA ) ( sec A + tan A) =1
RHS
=(sec A - sec A sin A) ( sec A + tan A)
=sec 2A - sec 2A sin A + secA tan A- sec A sin A tan A
=1/ cos2A - sin A /cos2A + sin A/ cos2A -- sin2A / cos2A
=sec2A -- tan2A
=1 LHS
tan 2A - Tan2B = sin2A - sin2B /cos2A cos2B
this qn LHS request clarify
Answered by | 24th Apr, 2008, 10:39: PM
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