prove
Asked by
| 24th Apr, 2008,
06:59: PM
Expert Answer:
tan2A - sin2A =tan2A . sin2A
RHS
sin2A/cos2A --sin2A
= sin2A -- sin2A. cos2A / cos2A
=sin2A ( 1- cos2A ) / cos2A
=tan2A . sin2A LHS
1+ sin A /1 - sin A =( sec A + tan A)2
RHS
( 1 + sin A) ( 1+ sin A) / 1 -- sin2A
= ( 1 + sin A )2 / cos2A
=1 + sin2A + 2 sinA / cos2A
=1/cos2A + sin2A / cos 2A+ 2 sin A/ cos A .1/cosA
=sec2A + tan2A + 2 tan A sec A
= ( sec A + tan A )2
Answered by
| 24th Apr, 2008,
11:28: PM
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