Asked by | 4th Jul, 2008, 09:30: PM
the quadrilateral is cyclic.
thus, sum of opposite angles of the quadrilateral is 180o.
that is, A+C = 180 and B+D = 180
cos(180-A) + cos(180+B) + cos(180+C) - sin(90+D)
= - [cosA+cosC] - [CosB+cosD]
Answered by | 15th Jul, 2008, 09:48: AM
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