CBSE Class 11-science Answered
Prove
Asked by | 04 Jul, 2008, 09:30: PM
Expert Answer
the quadrilateral is cyclic.
thus, sum of opposite angles of the quadrilateral is 180o.
that is, A+C = 180 and B+D = 180
consider L.H.S.,
cos(180-A) + cos(180+B) + cos(180+C) - sin(90+D)
= -cosA-cosB-cosC-cosD
= - [cosA+cosC] - [CosB+cosD]
Answered by | 15 Jul, 2008, 09:48: AM
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