Prove
Asked by | 17th Sep, 2008, 07:17: PM
Expert Answer:
tan(a+b) = (tana+tanb) / (1-tana tanb)
tan(a-b) = (tana-tanb) / (1+tana tanb)
so tan(π/4 + θ) + tan(π/4 - θ) = (1+tan θ) /(1-tan θ) + (1-tan θ) / (1+tan θ)
= (1+tan θ)2 +(1-tan θ)2 / (1-tan2θ)
=2(1+tan2θ)/ (1-tan2θ) = 2/cos2θ =2sec2θ
Answered by | 18th Sep, 2008, 01:02: PM
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