prove- work done=1/2mv^2-1/2mu^2

Asked by  | 11th Feb, 2012, 05:16: PM

Expert Answer:

Work done = force x displacement
for a uniformly accelerated motion v2-u2= 2as     and F= mxa
so W= (ma)x( v2-u2)/2a= 1/2m( v2-u2)

Answered by  | 11th Feb, 2012, 06:21: PM

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