PROVE THE FOLLOWING STATEMENT :
Asked by | 16th Apr, 2008, 08:12: PM
If a number is of the type 4k + 2 it is even.
If an even number is square, then it is the square of an even number, not the square of an odd number.
Square of an even number, say 2n, is 4n^2, which is a multiple of 4. So if an even number is a square, it has to be a multiple of 4.
But 4k+2 is not a multiple of 4. When you divide it by 4 you get a remainder of 2, not zero.
Answered by | 15th May, 2008, 09:23: PM
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