CBSE Class 9 Answered
prove that --
Asked by harshitalohia | 05 Feb, 2010, 08:07: PM
Expert Answer
the diagonals of a rhombus intersect each other at 90 degrees.
suppose,
ABCD is the rhombus and a circle is drawn with AB as diameter.
let P be the point of intersection of the diagonals.
now,angle APB=90 degrees.
so
any circle with AB as diameter must pass thru Pp(since the angle in a semi circle is always 90 degrees)
Answered by | 06 Feb, 2010, 05:59: PM
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