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CBSE Class 9 Answered

prove that --
Asked by harshitalohia | 05 Feb, 2010, 08:07: PM
answered-by-expert Expert Answer

the diagonals of a rhombus intersect each other at 90 degrees.

suppose,

 ABCD is the rhombus and a circle is drawn with AB as diameter.

 let P be the point of intersection of the diagonals.

now,angle APB=90 degrees.

so

any circle with AB as diameter must pass thru Pp(since the angle in a semi circle is always 90 degrees)

Answered by | 06 Feb, 2010, 05:59: PM
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