prove that --

Asked by harshitalohia | 5th Feb, 2010, 08:07: PM

Expert Answer:

the diagonals of a rhombus intersect each other at 90 degrees.


 ABCD is the rhombus and a circle is drawn with AB as diameter.

 let P be the point of intersection of the diagonals.

now,angle APB=90 degrees.


any circle with AB as diameter must pass thru Pp(since the angle in a semi circle is always 90 degrees)

Answered by  | 6th Feb, 2010, 05:59: PM

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