prove that --
Asked by harshitalohia | 5th Feb, 2010, 08:07: PM
the diagonals of a rhombus intersect each other at 90 degrees.
ABCD is the rhombus and a circle is drawn with AB as diameter.
let P be the point of intersection of the diagonals.
now,angle APB=90 degrees.
any circle with AB as diameter must pass thru Pp(since the angle in a semi circle is always 90 degrees)
Answered by | 6th Feb, 2010, 05:59: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number