Prove that.....

Asked by  | 25th Aug, 2008, 08:34: PM

Expert Answer:

cos(x/2)*cos(x/4)*cos(x/8)..........=(sinx)/x

taking log on both sides, we get,

log[cos(x/2)]+log[cos(x/4)]....=log [sinx]-logx

taking derivative on both sides wrt x, we get,

-(1/2)(tan[x/2])-(1/4)tan(x/4)-...= -tanx -(1/x)

taking derivative again,

we get the result.

Answered by  | 19th Mar, 2009, 08:38: AM

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