prove that

Asked by  | 6th Jun, 2008, 07:32: PM

Expert Answer:

1/(cosecA-cotA)

= 1/ [(1/sinA)-(cosA/sinA)]

= 1/ [(1-cosA)/sinA]

= sinA/(1-cosA)

= sinA(1+cosA)/(1-cosA)(1+cosA)

= (sinA+sinAcosA)/(1-cos2A)

= (sinA+sinAcosA)/sin2A

= sinA/sin2A + sinAcosA/sin2A

= 1/sinA + cosA/sinA

= cosecA + cotA

Answered by  | 7th Jun, 2008, 08:25: PM

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