Prove that ..
Asked by | 8th Mar, 2008, 09:48: PM
If an even number is square, then it is the square of an even number, not the square of an odd number.
Square of an even number, say 2n, is 4n^2, which is a multiple of 4. So if an even number is a square, it has to be a multiple of 4.
But 4k+2 is not a multiple of 4. When you divide it by 4 you get a remainder of 2, not zero.
Answered by | 17th Mar, 2008, 02:24: PM
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