CBSE Class 10 Answered
prove that
Asked by chiku999 | 20 Oct, 2009, 03:33: PM
This is alternate segment theorem which states that an angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment.
To Prove: ÐPTB = ÐPQT
Proof:
ÐSPT = 90° (rt. Ð in a semicircle)
Ðx + Ðy = 90° ( Ð sum of ∆)
Ðy + Ðz = 90° ( tan rad.)
Ðx = Ðz
ÐPTB = ÐPST
ÐPST = ÐPQT ( Ðs in same segment)
ÐPTB = ÐPQT
Answered by | 21 Oct, 2009, 03:54: PM
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