prove that

Asked by chiku999 | 20th Oct, 2009, 03:33: PM

Expert Answer:

This is  alternate segment theorem which states that an angle between a tangent and a chord through the point of contact is equal to the angle in the alternate segment. 

To Prove:  ÐPTB = ÐPQT


      ÐSPT = 90° (rt. Ð in a semicircle)

Ðx + Ðy = 90° ( Ð sum of ∆)
Ðy + Ðz = 90° ( tan rad.)
            Ðx = Ðz
     ÐPTB = ÐPST
     ÐPST = ÐPQT ( Ðs in same segment)

     ÐPTB = ÐPQT

Answered by  | 21st Oct, 2009, 03:54: PM

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